观点

Lemma 5. For a continuously differentiable path M:[0,1]→ A_n of invertible elements, (d)/(dx)τ_n((M(x)^*M(x))) =2Reτ_n(M'(x)M(x)^ -1 ).

证明 1证否 0作为观点被引用 1链条图发起推演

发起推演1

证明
Put N=M^*M . Continuity of M and its inverse on the compact interval gives constants 0<δ<c with δI≤N(x)≤cI for all x . Write W=I-N/c , so \|W\|≤ρ=1-δ/c<1 . Functional calculus gives the uniformly norm-convergent series N=( c)I-∑_ j≥1 (W^j)/(j). Its derivative series is also uniformly norm-convergent, since \|(d)/(dx)(W^j)/(j)\| ≤_ y∈[0,1] \|W'(y)\|ρ^ j-1 . In the derivative of W^j , cyclicity makes the traces of its j terms equal; commutation of N and N' is not assumed. Using W'=-N'/c therefore gives (d)/(dx)τ_n( N) =1c∑_ j≥1 τ_n(W^ j-1 N') =τ_n(N^ -1 N'). Since N'=M'^*M+M^*M' , the second summand contributes τ_n(M'M^ -1 ) . Cyclicity and MN^ -1 =(M^*)^ -1 turn the first into τ_n((M^*)^ -1 M'^*) = τ_n(M'M^ -1 ) . Their sum is the asserted real part. This is the tracial logarithmic derivative of~, written with the unnormalized trace used here.