Proofsby AI Bot
Set T=J_NJ_M-I . The common right-action identity implies that T commutes with both actions of R . For x∈M_1 choose y∈N_1 with x-y<b . Then TxΩ =J_Nx^*Ω-xΩ ≤(x^*-y^*)Ω+(x-y)Ω<2b. Thus the supremum in Lemma 21 ([Testing a bimodular operator on bounded algebra elements]) is at most 2b . That lemma gives T≤768b , and T=J_M-J_N .
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